JAVA EXAMPLE PROGRAMS

JAVA EXAMPLE PROGRAMS

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Java Exception Handling - Multiple Cache Blocks Examples

  • A single try block can have multiple catch blocks. This is required when the try block has statements that generates different types of exceptions.
  • If the first catch block contains the Exception class object then the subsequent catch blocks are never executed.
  • The last catch block in multiple catch blocks must contain the Exception class object. This is because, the java complier gives an error saying that the subsequent catch blocks haven't been reached. This is known as Unreachable code problem.

Multiple Cache Blocks Sample Code

Code:
package com.myjava.exceptions;

import java.net.MalformedURLException;
import java.net.URL;

public class MyMultipleCatchBlocks {
    
    public static void main(String a[]){
        MyMultipleCatchBlocks mmcb = new MyMultipleCatchBlocks();
        mmcb.execute(1);
        mmcb.execute(2);
    }
    
    public void execute(int i){
        try{
            if(i == 1){
                getIntValue("7u");
            } else {
                getUrlObj("www.junksite.com");
            }
        } catch (NumberFormatException nfe){
            System.out.println("Inside NumberFormatException... "+nfe.getMessage());
        } catch (MalformedURLException mue){
            System.out.println("Inside MalformedURLException... "+mue.getMessage());
        } catch (Exception ex){
            System.out.println("Inside Exception... "+ex.getMessage());
        }
    }
    public int getIntValue(String num){
        return Integer.parseInt(num);
    }
    
    public URL getUrlObj(String urlStr) throws MalformedURLException{
        return new URL(urlStr);
    }
}

Example Output

Inside NumberFormatException... For input string: "7u"
Inside MalformedURLException... no protocol: www.junksite.com

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Knowledge Centre
String Vs StringBuffer
We know that String is immutable object. We can not change the value of a String object once it is initiated. If we try to change the value of the existing String object then it creates new object rather than changing the value of the existing object. So incase, we are going to do more modificatios on String, then use StringBuffer. StringBuffer updates the existing objects value, rather creating new object.
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Reference: Java™ Platform Standard Ed. 7 - API Specification | Java is registered trademark of Oracle.
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