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Program: How to validate IP address using regular expression?


Below example gives sample code for validation IP address using regular expression.

package com.java2novice.regex;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MyIpMatch {

	public static boolean isValidIP(String ipAddr){
		Pattern ptn = Pattern.compile("^(\\d{1,3})\\.(\\d{1,3})\\.(\\d{1,3})\\.(\\d{1,3})$");
		Matcher mtch = ptn.matcher(ipAddr);
		return mtch.find();

	public static void main(String a[]){
		System.out.println(" is valid? "+MyIpMatch.isValidIP(""));
		System.out.println("10.2a.56.32 is valid? "+MyIpMatch.isValidIP("10.2a.56.32"));
		System.out.println("10.23.45 is valid? "+MyIpMatch.isValidIP("10.23.45"));

Output: is valid? true
10.2a.56.32 is valid? false
10.23.45 is valid? false
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Knowledge Centre
Pass by value Vs Pass by reference
Pass by value: Passing a copy of the value, not the original reference.

Pass by reference: Passsing the address of the object, so that you can access the original object.
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About Author

I'm Nataraja Gootooru, programmer by profession and passionate about technologies. All examples given here are as simple as possible to help beginners. The source code is compiled and tested in my dev environment.

If you come across any mistakes or bugs, please email me to [email protected].

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Reference: Java™ Platform Standard Ed. 7 - API Specification | Java™ Platform Standard Ed. 8 - API Specification | Java is registered trademark of Oracle.
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