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Program: Find Nth node from the end of Linked List

Problem Description:

Write a program to identify Nth node from the end of Linked List.

We have two approaches to identify Nth node from the end.

In First Approach:

  • First iterate through linked list and identify length.
  • Then again iterate (lenght-N) nodes from from head node.
  • The Node after the above iteration is the Nth node from the end.

In Second Approach:

  • We will define two temp Node references and they will be initially pointed to head node.
  • The two temp nodes are called as reference node & main node.
  • First iterate reference node to N nodes.
  • Then iterate both temp nodes one step at a time, till reference node is null.
  • Once after the above iteration, the main node represents the Nth node from the end node.

package com.java2novice.ds.linkedlist;

public class LlNthNodeFromLast {

    static class Node {
        int data;
        Node next;
        Node(int tmp) {data = tmp;}

    static Node findNthNodeFromLastV1(Node head, int n) {

         * In this approach, first identify the length of the list.
         * Then do lenght-n iterations from head to reach nth node from last.
        int length = 0;
        Node temp = head;
        while(temp != null) {
            temp =;
        System.out.println("length: "+length);
        for(int i=0;i<length-n;i++) {
            head =;
        return head;

    static Node findNthNodeFromLastV2(Node head, int n) {

         * In this approach, we will use two pointers like refNode & mainNode
         * First we will traverse refNode by n times.
         * Then we will traverse both nodes one step at a time till refNode reaches null
         * The mainNode is the one we are looking for.
        Node refNode = head;
        Node mainNode = head;
        if(head == null) {
            return null;
        for(int i=0;i<n;i++) {
            if(refNode == null) {
                System.out.println("The n input size is more than linked list size");
                return null;
            refNode =;

        while(refNode != null) {
            mainNode =;
            refNode =;

        return mainNode;

    public static void main(String[] a) {

        Node n1 = new Node(23);
        Node n2 = new Node(29);
        Node n3 = new Node(69);
        Node n4 = new Node(85);
        Node n5 = new Node(40);
        Node n6 = new Node(45);
        Node n7 = new Node(54); = n2; = n3; = n4; = n5; = n6; = n7;

        Node nthNode = findNthNodeFromLastV2(n1, 3);
        System.out.println("Nth node value: ";

Nth node value: 40
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I'm Nataraja Gootooru, programmer by profession and passionate about technologies. All examples given here are as simple as possible to help beginners. The source code is compiled and tested in my dev environment.

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