JAVA EXAMPLE PROGRAMS

JAVA EXAMPLE PROGRAMS

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How to compare StringBuffer object to String object in java?


Description:

The below example shows how to compare StringBuffer object with String object. String object provides contentEquals() method to compare content with a StringBuffer object.


Code:
package com.myjava.string;

public class MyStringComp {

    public static void main(String a[]){
    
        String c = "We are comparing the content with a StringBuffer content";
        StringBuffer sb =
			new StringBuffer("We are comparing the content with a StringBuffer content");
        /**
         * We can use contentEquals() method to compare content with a StringBuffer.
         * It returns boolean value.
         */
        if(c.contentEquals(sb)){
            System.out.println("The content is equal");
        } else {
            System.out.println("The content is not equal");
        }
        StringBuffer asb =
			new StringBuffer("You cannot compare the content with a String content");
        if(c.contentEquals(asb)){
            System.out.println("The content is equal");
        } else {
            System.out.println("The content is not equal");
        }
    }
}

Example Output

The content is equal
The content is not equal

Other String Function Examples

Knowledge Centre
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As you know, destory() is part of servlet life cycle methods, it is used to kill the servlet instance. Servlet Engine is used to call destory(). In case, if you call destory method from service(), it just execute the code written in the destory(), but it wont kill the servlet instance. destroy() will be called before killing the servlet instance by servlet engine.
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About Author

I'm Nataraja Gootooru, programmer by profession and passionate about technologies. All examples given here are as simple as possible to help beginners. The source code is compiled and tested in my dev environment.

If you come across any mistakes or bugs, please email me to [email protected].

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Reference: Java™ Platform Standard Ed. 7 - API Specification | Java™ Platform Standard Ed. 8 - API Specification | Java is registered trademark of Oracle.
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